| Oracle® Database Administrator's Guide 11g Release 2 (11.2) Part Number E25494-02 |
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PDF · Mobi · ePub |
| Oracle® Database Administrator's Guide 11g Release 2 (11.2) Part Number E25494-02 |
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PDF · Mobi · ePub |
You create a hash cluster using a CREATE CLUSTER statement, but you specify a HASHKEYS clause. The following statement creates a cluster named trial_cluster, clustered by the trialno column (the cluster key):
CREATE CLUSTER trial_cluster ( trialno NUMBER(5,0) )
TABLESPACE users
STORAGE ( INITIAL 250K
NEXT 50K
MINEXTENTS 1
MAXEXTENTS 3
PCTINCREASE 0 )
HASH IS trialno
HASHKEYS 150;
The following statement creates the trial table in the trial_cluster hash cluster:
CREATE TABLE trial (
trialno NUMBER(5,0) PRIMARY KEY,
... )
CLUSTER trial_cluster (trialno);
As with index clusters, the key of a hash cluster can be a single column or a composite key (multiple column key). In the preceding example, the key is the trialno column.
The HASHKEYS value, in this case 150, specifies and limits the number of unique hash values that the hash function can generate. The database rounds the number specified to the nearest prime number.
If no HASH IS clause is specified, then the database uses an internal hash function. If the cluster key is already a unique identifier that is uniformly distributed over its range, then you can bypass the internal hash function and specify the cluster key as the hash value, as in the preceding example. You can also use the HASH IS clause to specify a user-defined hash function.
You cannot create a cluster index on a hash cluster, and you need not create an index on a hash cluster key.
The following sections explain and provide guidelines for setting the parameters of the CREATE CLUSTER statement specific to hash clusters:
See Also:
Chapter 22, "Managing Clusters" for additional information about creating tables in a cluster, guidelines for setting parameters of theCREATE CLUSTER statement common to index and hash clusters, and the privileges required to create any clusterA sorted hash cluster stores the rows corresponding to each value of the hash function in such a way that the database can efficiently return them in sorted order. For applications that always consume data in sorted order, sorted hash clusters can retrieve data faster by minimizing logical I/Os.
Assume that a telecommunications company stores detailed call records for a fixed number of originating telephone numbers through a telecommunications switch. From each originating telephone number there can be an unlimited number of calls.
The application stores calls records as calls are made. Each call has a detailed call record identified by a timestamp. For example, the application stores a call record with timestamp 0, then a call record with timestamp 1, and so on.
When generating bills for each originating phone number, the application processes them in first-in, first-out (FIFO) order. The following table shows sample details for three originating phone numbers:
| telephone_number | call_timestamp |
|---|---|
| 6505551212 | 0, 1, 2, 3, 4, ... |
| 6505551213 | 0, 1, 2, 3, 4, ... |
| 6505551214 | 0, 1, 2, 3, 4, ... |
In the following SQL statements, the telephone_number column is the hash key. The hash cluster is sorted on the call_timestamp and call_duration columns. The example uses the same names for the clustering and sorting columns in the table definition as in the cluster definition, but this is not required. The number of hash keys is based on 10-digit telephone numbers.
CREATE CLUSTER call_detail_cluster ( telephone_number NUMBER, call_timestamp NUMBER SORT, call_duration NUMBER SORT ) HASHKEYS 10000 HASH IS telephone_number SIZE 256; CREATE TABLE call_detail ( telephone_number NUMBER, call_timestamp NUMBER SORT, call_duration NUMBER SORT, other_info VARCHAR2(30) ) CLUSTER call_detail_cluster ( telephone_number, call_timestamp, call_duration );
Suppose that you seed the call_detail table with the rows in FIFO order as shown in Example 23-1.
Example 23-1 Data Inserted in Sequential Order
INSERT INTO call_detail VALUES (6505551212, 0, 9, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 1, 17, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 2, 5, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 3, 90, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 0, 35, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 1, 6, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 2, 4, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 3, 4, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 0, 15, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 1, 20, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 2, 1, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 3, 25, 'misc info'); COMMIT;
In Example 23-2, you SET AUTOTRACE ON, and then query the call_detail table for the call details for the phone number 6505551212.
Example 23-2 Querying call_detail
SQL> SET AUTOTRACE ON;
SQL> SELECT * FROM call_detail WHERE telephone_number = 6505551212;
TELEPHONE_NUMBER CALL_TIMESTAMP CALL_DURATION OTHER_INFO
---------------- -------------- ------------- ------------------------------
6505551212 0 9 misc info
6505551212 1 17 misc info
6505551212 2 5 misc info
6505551212 3 90 misc info
Execution Plan
----------------------------------------------------------
Plan hash value: 2118876266
----------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)|
----------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 56 | 0 (0)|
|* 1 | TABLE ACCESS HASH| CALL_DETAIL | 1 | 56 | |
----------------------------------------------------------------------
Example 23-2 shows that the query retrieves the rows ordered by timestamp even though no sort appears in the query plan.
Suppose you then delete the existing rows and insert the same rows out of sequence:
DELETE FROM call_detail; INSERT INTO call_detail VALUES (6505551213, 3, 4, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 0, 15, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 0, 9, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 1, 20, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 2, 1, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 1, 6, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 2, 4, 'misc info'); INSERT INTO call_detail VALUES (6505551214, 3, 25, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 1, 17, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 2, 5, 'misc info'); INSERT INTO call_detail VALUES (6505551212, 3, 90, 'misc info'); INSERT INTO call_detail VALUES (6505551213, 0, 35, 'misc info'); COMMIT;
If you rerun the same query of call_detail, the database again retrieves the rows in sorted order even though no ORDER BY clause is specified. No SORT ORDER BY operation appears in the query plan because the database performs an internal sort.
Now assume that you create a nonclustered table call_detail_nonclustered and then load it with the same sample values in Example 23-1. To retrieve the data in sorted order, you must use an ORDER BY clause as follows:
SQL> SELECT * FROM call_detail_nonclustered WHERE telephone_number = 6505551212
2 ORDER BY call_timestamp, call_duration;
TELEPHONE_NUMBER CALL_TIMESTAMP CALL_DURATION OTHER_INFO
---------------- -------------- ------------- ------------------------------
6505551212 0 9 misc info
6505551212 1 17 misc info
6505551212 2 5 misc info
6505551212 3 90 misc info
Execution Plan
----------------------------------------------------------
Plan hash value: 2555750302
----------------------------------------------------------------------------------
|Id| Operation | Name |Rows|Bytes|Cost (%CPU)|Time |
----------------------------------------------------------------------------------
| 0| SELECT STATEMENT | | 4 | 224 | 4 (25)| 00:00:01 |
| 1| SORT ORDER BY | | 4 | 224 | 4 (25)| 00:00:01 |
|*2| TABLE ACCESS FULL| CALL_DETAIL_NONCLUSTERED | 4 | 224 | 3 (0)| 00:00:01 |
----------------------------------------------------------------------------------
The preceding plan shows that in the nonclustered case the sort is more expensive than in the clustered case. The rows, bytes, cost, and time are all greater in the case of the table that is not stored in a sorted hash cluster.
You can also create a single-table hash cluster, which provides fast access to rows in a table. However, this table must be the only table in the hash cluster. Essentially, there must be a one-to-one mapping between hash keys and data rows. The following statement creates a single-table hash cluster named peanut with the cluster key variety:
CREATE CLUSTER peanut (variety NUMBER) SIZE 512 SINGLE TABLE HASHKEYS 500;
The database rounds the HASHKEYS value up to the nearest prime number, so this cluster has a maximum of 503 hash key values, each of size 512 bytes. The SINGLE TABLE clause is valid only for hash clusters. HASHKEYS must also be specified.
When creating a hash cluster, it is important to choose the cluster key correctly and set the HASH IS, SIZE, and HASHKEYS parameters so that performance and space use are optimal. The following guidelines describe how to set these parameters.
Choosing the correct cluster key is dependent on the most common types of queries issued against the clustered tables. For example, consider the emp table in a hash cluster. If queries often select rows by employee number, the empno column should be the cluster key. If queries often select rows by department number, the deptno column should be the cluster key. For hash clusters that contain a single table, the cluster key is typically the entire primary key of the contained table.
The key of a hash cluster, like that of an index cluster, can be a single column or a composite key (multiple column key). A hash cluster with a composite key must use the internal hash function of the database.
Specify the HASH IS parameter only if the cluster key is a single column of the NUMBER data type, and contains uniformly distributed integers. If these conditions apply, you can distribute rows in the cluster so that each unique cluster key value hashes, with no collisions (two cluster key values having the same hash value), to a unique hash value. If these conditions do not apply, omit this clause so that you use the internal hash function.
SIZE should be set to the average amount of space required to hold all rows for any given hash key. Therefore, to properly determine SIZE, you must be aware of the characteristics of your data:
If the hash cluster is to contain only a single table and the hash key values of the rows in that table are unique (one row for each value), SIZE can be set to the average row size in the cluster.
If the hash cluster is to contain multiple tables, SIZE can be set to the average amount of space required to hold all rows associated with a representative hash value.
Further, once you have determined a (preliminary) value for SIZE, consider the following. If the SIZE value is small (more than four hash keys can be assigned for each data block) you can use this value for SIZE in the CREATE CLUSTER statement. However, if the value of SIZE is large (four or fewer hash keys can be assigned for each data block), then you should also consider the expected frequency of collisions and whether performance of data retrieval or efficiency of space usage is more important to you.
If the hash cluster does not use the internal hash function (if you specified HASH IS) and you expect few or no collisions, you can use your preliminary value of SIZE. No collisions occur and space is used as efficiently as possible.
If you expect frequent collisions on inserts, the likelihood of overflow blocks being allocated to store rows is high. To reduce the possibility of overflow blocks and maximize performance when collisions are frequent, you should adjust SIZE as shown in the following chart.
| Available Space for each Block / Calculated SIZE | Setting for SIZE |
|---|---|
| 1 | SIZE |
| 2 | SIZE + 15% |
| 3 | SIZE + 12% |
| 4 | SIZE + 8% |
| >4 | SIZE |
Overestimating the value of SIZE increases the amount of unused space in the cluster. If space efficiency is more important than the performance of data retrieval, disregard the adjustments shown in the preceding table and use the original value for SIZE.
For maximum distribution of rows in a hash cluster, the database rounds the HASHKEYS value up to the nearest prime number.
The following examples show how to correctly choose the cluster key and set the HASH IS, SIZE, and HASHKEYS parameters. For all examples, assume that the data block size is 2K and that on average, 1950 bytes of each block is available data space (block size minus overhead).
You decide to load the emp table into a hash cluster. Most queries retrieve employee records by their employee number. You estimate that the maximum number of rows in the emp table at any given time is 10000 and that the average row size is 55 bytes.
In this case, empno should be the cluster key. Because this column contains integers that are unique, the internal hash function can be bypassed. SIZE can be set to the average row size, 55 bytes. Note that 34 hash keys are assigned for each data block. HASHKEYS can be set to the number of rows in the table, 10000. The database rounds this value up to the next highest prime number: 10007.
CREATE CLUSTER emp_cluster (empno NUMBER) . . . SIZE 55 HASH IS empno HASHKEYS 10000;
Conditions similar to the previous example exist. In this case, however, rows are usually retrieved by department number. At most, there are 1000 departments with an average of 10 employees for each department. Department numbers increment by 10 (0, 10, 20, 30, . . .).
In this case, deptno should be the cluster key. Since this column contains integers that are uniformly distributed, the internal hash function can be bypassed. A preliminary value of SIZE (the average amount of space required to hold all rows for each department) is 55 bytes * 10, or 550 bytes. Using this value for SIZE, only three hash keys can be assigned for each data block. If you expect some collisions and want maximum performance of data retrieval, slightly alter your estimated SIZE to prevent collisions from requiring overflow blocks. By adjusting SIZE by 12%, to 620 bytes (see "Setting SIZE"), there is more space for rows from expected collisions.
HASHKEYS can be set to the number of unique department numbers, 1000. The database rounds this value up to the next highest prime number: 1009.
CREATE CLUSTER emp_cluster (deptno NUMBER) . . . SIZE 620 HASH IS deptno HASHKEYS 1000;
As with index clusters, it is important to estimate the storage required for the data in a hash cluster.
Oracle Database guarantees that the initial allocation of space is sufficient to store the hash table according to the settings SIZE and HASHKEYS. If settings for the storage parameters INITIAL, NEXT, and MINEXTENTS do not account for the hash table size, incremental (additional) extents are allocated until at least SIZE*HASHKEYS is reached. For example, assume that the data block size is 2K, the available data space for each block is approximately 1900 bytes (data block size minus overhead), and that the STORAGE and HASH parameters are specified in the CREATE CLUSTER statement as follows:
STORAGE (INITIAL 100K
NEXT 150K
MINEXTENTS 1
PCTINCREASE 0)
SIZE 1500
HASHKEYS 100
In this example, only one hash key can be assigned for each data block. Therefore, the initial space required for the hash cluster is at least 100*2K or 200K. The settings for the storage parameters do not account for this requirement. Therefore, an initial extent of 100K and a second extent of 150K are allocated to the hash cluster.
Alternatively, assume the HASH parameters are specified as follows:
SIZE 500 HASHKEYS 100
In this case, three hash keys are assigned to each data block. Therefore, the initial space required for the hash cluster is at least 34*2K or 68K. The initial settings for the storage parameters are sufficient for this requirement (an initial extent of 100K is allocated to the hash cluster).
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